If an URL path element contains %2F (an escaped "/") Flask.route considers it as an unescaped slash. · Issue #900 · pallets/flask

Here's an example: from flask import Flask app = Flask(__name__) @app.route('/<urlvar>') def hello_world(urlvar): return 'Hello World! ' + repr(urlvar) if __name__ == '__main__': app.run(debug=True...</urlvar>